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0.25x^2+1.5=1.25x
We move all terms to the left:
0.25x^2+1.5-(1.25x)=0
We add all the numbers together, and all the variables
0.25x^2-(+1.25x)+1.5=0
We get rid of parentheses
0.25x^2-1.25x+1.5=0
a = 0.25; b = -1.25; c = +1.5;
Δ = b2-4ac
Δ = -1.252-4·0.25·1.5
Δ = 0.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.25)-\sqrt{0.0625}}{2*0.25}=\frac{1.25-\sqrt{0.0625}}{0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.25)+\sqrt{0.0625}}{2*0.25}=\frac{1.25+\sqrt{0.0625}}{0.5} $
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